a. -1
b. -1/2
c. 0
d. 1/2
e. 1
TOLONG DI BANTU PAKAI CARA MENYELESAIKANNYA JUGA KAK, TERIMAKASIH..
ITU ADA 2 SOAL KAK...
Penjelasan dengan langkah-langkah:
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TRIGONOMETRI
Ingat rumus-rumus berikut
[tex]\boxed{(a - b)^2 = a^2 - 2ab + b^2}[/tex]
[tex]\boxed{\sin^2 t + \cos ^2 t = 1}[/tex]
[tex]\boxed{\sec^2 \theta = \frac{1}{1 - \sin ^2 \theta}}[/tex]
[tex]\boxed{\sin(a)^2 = \sin ^2 a}[/tex]
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hasil dari (sin x - cos x)² + 2sin x cos x
[tex]\tt (\sin x - \cos x)^2 + 2\sin x \cos x[/tex]
[tex]\tt = \sin^2 x - 2\sin x \cos x + cos^2 x + 2\sin x \cos x[/tex]
[tex]= \tt \sin^2 x + \cos ^2 x[/tex]
[tex]= \tt 1 \:\:\text{[Opsi E]}[/tex]
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[tex]\displaystyle \tt \frac{2 - \sec ^2 \alpha}{\sec ^ 2\alpha}[/tex]
[tex]\displaystyle \tt = \frac{2 - \frac{1}{1 - \sin ^ 2 \alpha}}{\frac{1}{1 - \sin ^2 \alpha}}[/tex]
[tex]\displaystyle \tt = \frac{ \frac{2(1 - \sin^{2} \alpha ) - 1 }{1 - \sin ^{2} \alpha } }{ \frac{1}{1 - \sin ^{2} \alpha } } [/tex]
[tex]\displaystyle \tt = \frac{2 - 2\sin ^2 \alpha - 1}{1}[/tex]
[tex]= \tt 2 - 2\sin ^2 \alpha - 1[/tex]
[tex]= \tt 1 - 2 \sin ^2 \alpha \:\:\:\text{[Opsi E]}[/tex]
[answer.2.content]
